Finding The Radius Of A Circle Given Its Equation X^2+y^2-2x+8y-47=0

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Finding the radius of a circle when given its equation might seem daunting at first, but with a clear understanding of the underlying principles and a step-by-step approach, it becomes a straightforward task. This article delves deep into the process of determining the radius of a circle from its equation, specifically focusing on equations in the general form. We'll break down the concepts, provide detailed explanations, and illustrate the method with examples, ensuring you grasp the fundamentals and can confidently tackle similar problems.

Decoding the General Equation of a Circle

The general equation of a circle is expressed as x² + y² + 2gx + 2fy + c = 0. This form might appear complex initially, but it holds valuable information about the circle's properties. The key lies in transforming this general form into the standard form of a circle's equation, which readily reveals the circle's center and radius. The standard form, (x - h)² + (y - k)² = r², is your gateway to unlocking these details, where (h, k) represents the coordinates of the circle's center, and r signifies the radius. Mastering the conversion from general to standard form is crucial for solving a multitude of circle-related problems, and this article serves as your comprehensive guide to achieving this proficiency.

To effectively convert from the general to the standard form, a technique called completing the square is employed. This algebraic manipulation allows us to rewrite quadratic expressions into perfect square trinomials, which are essential for revealing the circle's center and radius. Let's dissect the general equation x² + y² + 2gx + 2fy + c = 0 to understand how completing the square comes into play. We focus on grouping the x terms and the y terms together: (x² + 2gx) + (y² + 2fy) + c = 0. Our aim is to transform the expressions within the parentheses into perfect squares. This involves adding and subtracting specific constants to both the x and y groupings. For the x terms, we add and subtract g², and for the y terms, we add and subtract f². This process ensures that we don't change the equation's overall value while creating the desired perfect squares. The transformed equation then becomes (x² + 2gx + g²) + (y² + 2fy + f²) + c - g² - f² = 0. Now, the expressions in parentheses can be elegantly rewritten as squared terms: (x + g)² + (y + f)² = g² + f² - c. This is the standard form, revealing the center as (-g, -f) and the radius as √(g² + f² - c). This transformation is a powerful tool, allowing us to extract the geometric properties of a circle directly from its algebraic representation. By understanding the mechanics of completing the square and its application to the general equation of a circle, you gain a profound ability to analyze and interpret circular forms in various mathematical contexts.

Understanding this conversion process not only allows you to find the radius but also gives you a deeper understanding of the relationship between the equation and the geometric properties of the circle. The center, determined by (-g, -f), and the radius, calculated as √(g² + f² - c), are fundamental characteristics that define the circle's position and size on the coordinate plane. By mastering the conversion from general to standard form, you unlock the ability to quickly and accurately extract these properties, enabling you to solve a wide range of problems related to circles. This skill is essential in various fields, including geometry, calculus, and even physics, where circular motion and shapes are frequently encountered. The ability to analyze the equation of a circle and immediately grasp its geometric implications is a testament to the power of mathematical tools and their ability to bridge the gap between abstract algebra and concrete geometric concepts.

Step-by-Step Solution for the Given Equation

Let's apply this knowledge to the specific equation provided: x² + y² - 2x + 8y - 47 = 0. Our mission is to find the radius of the circle represented by this equation. We'll embark on this quest by meticulously following the steps outlined above, transforming the given equation into its standard form. This process will not only reveal the radius but also provide a deeper understanding of how the circle's equation encodes its geometric properties. The journey begins with grouping the x terms and the y terms together, paving the way for the crucial step of completing the square. We'll navigate through the algebraic manipulations with precision, ensuring each step brings us closer to our goal: the coveted radius of the circle.

Step 1: Group the x and y terms: The first strategic move involves rearranging the equation to group the x terms and y terms together. This sets the stage for completing the square, a technique that will allow us to rewrite the quadratic expressions in a more manageable form. By grouping the terms, we create a visual structure that highlights the expressions we need to manipulate. The equation x² + y² - 2x + 8y - 47 = 0 transforms into (x² - 2x) + (y² + 8y) - 47 = 0. This seemingly simple rearrangement is a crucial step, as it isolates the quadratic and linear terms for both x and y, making the subsequent steps of completing the square more intuitive and organized. This strategic grouping is not merely a cosmetic change; it's a fundamental step in unveiling the underlying structure of the circle's equation and paving the way for the extraction of its key geometric parameters: the center and the radius. The grouped form allows us to focus on each variable separately, simplifying the process of transforming the equation into the standard form, which directly reveals these parameters.

Step 2: Complete the square for x and y: Now, the heart of the process: completing the square. This technique allows us to rewrite quadratic expressions as perfect square trinomials, which are essential for obtaining the standard form of the circle's equation. For the x terms, we have x² - 2x. To complete the square, we take half of the coefficient of the x term (-2), which is -1, and square it, resulting in 1. Adding and subtracting this value within the parentheses, we get (x² - 2x + 1 - 1). The first three terms now form a perfect square trinomial: (x - 1)² - 1. We repeat this process for the y terms. We have y² + 8y. Half of the coefficient of the y term (8) is 4, and squaring it gives us 16. Adding and subtracting this value, we obtain (y² + 8y + 16 - 16). The first three terms again form a perfect square trinomial: (y + 4)² - 16. These transformations are the cornerstone of the process, allowing us to express the original quadratic expressions in a compact and insightful form. By completing the square, we've effectively reshaped the equation, bringing it closer to the standard form that readily reveals the circle's center and radius.

Step 3: Rewrite the equation in standard form: Having completed the square for both x and y, we can now rewrite the equation in its standard form. Substituting the completed square expressions back into the equation, we have: [(x - 1)² - 1] + [(y + 4)² - 16] - 47 = 0. This form is still a bit cluttered, so we simplify it by moving the constant terms to the right side of the equation: (x - 1)² + (y + 4)² = 1 + 16 + 47. This simplification isolates the squared terms on the left, bringing the equation closer to the standard form. Performing the addition on the right side, we arrive at: (x - 1)² + (y + 4)² = 64. This is the standard form of the circle's equation, and it's a treasure trove of information. It immediately reveals the circle's center as (1, -4) and the square of the radius as 64. This transformation is a pivotal moment in our journey, as it unveils the circle's key geometric properties with clarity and precision. The standard form is not just a mathematical representation; it's a visual snapshot of the circle's position and size on the coordinate plane.

Step 4: Determine the radius: With the equation now in the standard form (x - 1)² + (y + 4)² = 64, determining the radius is a straightforward task. Recall that the standard form of a circle's equation is (x - h)² + (y - k)² = r², where r represents the radius. By comparing our equation to the standard form, we can see that r² = 64. To find the radius r, we simply take the square root of 64. The square root of 64 is 8, so the radius of the circle is 8 units. This final step brings our quest to a successful conclusion. We've not only found the radius but also reinforced the connection between the algebraic representation of a circle and its geometric properties. The radius, a fundamental characteristic of the circle, is now readily available thanks to our methodical application of completing the square and transforming the equation into its standard form. This process exemplifies the power of algebraic manipulation in unlocking geometric insights.

Therefore, the radius of the circle given by the equation x² + y² - 2x + 8y - 47 = 0 is 8 units.

Key Takeaways and Further Exploration

This exercise underscores the importance of mastering algebraic techniques like completing the square. The ability to manipulate equations and transform them into insightful forms is a cornerstone of mathematical problem-solving. In the context of circles, completing the square allows us to bridge the gap between the general equation and the standard form, unlocking the circle's center and radius with ease. This skill extends far beyond circle-specific problems; it's a valuable tool in various mathematical domains, including conic sections, quadratic equations, and calculus. By understanding the underlying principles and practicing the technique, you can develop a confident and versatile approach to tackling a wide range of mathematical challenges. The journey of learning mathematics is often about connecting seemingly disparate concepts, and completing the square is a prime example of such a connection, linking algebraic manipulation to geometric understanding.

Beyond the specific problem we've solved, there's a broader landscape of circle-related concepts to explore. You can delve deeper into the relationships between circles and lines, investigating tangents, secants, and chords. The concept of the unit circle, with its center at the origin and a radius of 1, is fundamental in trigonometry and serves as a powerful tool for understanding trigonometric functions. Conic sections, including circles, ellipses, parabolas, and hyperbolas, form a rich area of study, each with its unique properties and applications. Exploring these concepts will not only deepen your understanding of circles but also broaden your mathematical horizons. The world of mathematics is interconnected, and each topic builds upon the foundations laid by others. By continuously exploring and expanding your knowledge, you'll develop a more holistic and insightful understanding of the mathematical landscape.

In conclusion, finding the radius of a circle from its general equation involves a methodical process of completing the square and transforming the equation into its standard form. This skill is not just about solving a specific problem; it's about developing a deeper understanding of the relationship between algebra and geometry, and about acquiring a versatile tool that can be applied in various mathematical contexts. As you continue your mathematical journey, remember that practice and exploration are key to mastering new concepts and unlocking the beauty and power of mathematics.