Solving Radical Equations Finding X For Y = X + √(x + 5) And Y = 7

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In this comprehensive guide, we will delve into the process of finding all values of x that satisfy the conditions given by the equations y = x + √(x + 5) and y = 7. This problem falls under the realm of algebraic equations, specifically those involving radicals. Such equations often require a methodical approach to isolate the variable and eliminate the radical term. Let's embark on a step-by-step journey to unravel this mathematical puzzle.

Understanding the Problem

Before we dive into the solution, let's first understand the problem at hand. We are given two equations:

  1. y = x + √(x + 5)
  2. y = 7

Our goal is to find all values of x that make both equations true simultaneously. This means we need to find the x value(s) that, when plugged into the first equation, will result in y = 7. This involves dealing with a square root, which adds a layer of complexity to the problem. Understanding the domain of the square root function is also crucial, as we must ensure that the expression inside the square root is non-negative.

Step-by-Step Solution

Step 1: Substitute the Value of y

The first step is to substitute the value of y from the second equation into the first equation. Since y = 7, we can replace y in the first equation with 7. This gives us:

7 = x + √(x + 5)

Now we have a single equation with a single variable, x, which is a significant step forward.

Step 2: Isolate the Radical Term

Next, we need to isolate the radical term, √(x + 5), on one side of the equation. To do this, we subtract x from both sides of the equation:

7 - x = √(x + 5)

Now the radical term is by itself on the right side of the equation, which is essential for the next step.

Step 3: Square Both Sides

To eliminate the square root, we square both sides of the equation. This is a crucial step, but it's important to remember that squaring both sides can sometimes introduce extraneous solutions (solutions that satisfy the transformed equation but not the original equation). Therefore, we'll need to check our solutions later.

Squaring both sides of 7 - x = √(x + 5) gives us:

(7 - x)² = (√(x + 5))²

Expanding the left side and simplifying the right side, we get:

49 - 14x + x² = x + 5

Step 4: Rearrange into a Quadratic Equation

Now we have a quadratic equation. To solve it, we need to rearrange it into the standard form ax² + bx + c = 0. To do this, we subtract x and 5 from both sides:

x² - 14x + 49 - x - 5 = 0

Combining like terms, we get:

x² - 15x + 44 = 0

Step 5: Solve the Quadratic Equation

We can solve this quadratic equation using factoring, the quadratic formula, or completing the square. In this case, factoring is the easiest approach. We need to find two numbers that multiply to 44 and add up to -15. These numbers are -4 and -11. So, we can factor the quadratic equation as follows:

(x - 4)(x - 11) = 0

This gives us two possible solutions for x:

  • x - 4 = 0 => x = 4
  • x - 11 = 0 => x = 11

Step 6: Check for Extraneous Solutions

As mentioned earlier, squaring both sides of an equation can introduce extraneous solutions. Therefore, we must check both potential solutions in the original equation 7 = x + √(x + 5).

Checking x = 4

Substitute x = 4 into the original equation:

7 = 4 + √(4 + 5)

7 = 4 + √9

7 = 4 + 3

7 = 7

This solution is valid.

Checking x = 11

Substitute x = 11 into the original equation:

7 = 11 + √(11 + 5)

7 = 11 + √16

7 = 11 + 4

7 = 15

This solution is extraneous because it does not satisfy the original equation.

Final Answer

Therefore, the only value of x that satisfies the given conditions is x = 4. This methodical approach, involving isolating the radical, squaring both sides, solving the resulting quadratic, and checking for extraneous solutions, is a cornerstone technique in solving equations with radicals. Understanding each step and its implications is key to mastering these types of problems. Remember that the domain of the square root function requires the expression inside the square root to be non-negative, so always keep this in mind when checking for extraneous solutions.

Isolating the Radical

The first crucial step in solving equations involving radicals is to isolate the radical term. This means manipulating the equation to get the radical expression alone on one side. This typically involves adding or subtracting terms from both sides of the equation. Isolating the radical sets the stage for the next step, which is eliminating the radical by raising both sides of the equation to the appropriate power.

Squaring Both Sides (or Raising to the Appropriate Power)

To eliminate a square root, you square both sides of the equation. If you have a cube root, you cube both sides, and so on. This step is based on the property that (√a)² = a. However, it's extremely important to remember that squaring both sides can introduce extraneous solutions. This is because the operation of squaring can make two unequal quantities equal (e.g., -2 and 2 both become 4 when squared). Therefore, checking for extraneous solutions is a mandatory step.

Solving the Resulting Equation

After eliminating the radical, you'll often be left with a polynomial equation, such as a linear or quadratic equation. The techniques for solving these types of equations are well-established. Linear equations are solved by isolating the variable, while quadratic equations can be solved by factoring, using the quadratic formula, or completing the square. The specific method you choose will depend on the nature of the equation.

Checking for Extraneous Solutions

This is arguably the most critical step in solving radical equations. Extraneous solutions are potential solutions that arise from the process of squaring both sides (or raising to an even power) but do not satisfy the original equation. To check for extraneous solutions, you must substitute each potential solution back into the original equation and verify that it makes the equation true. If a potential solution does not satisfy the original equation, it is an extraneous solution and must be discarded.

Domain Considerations

When dealing with square roots (or other even-indexed radicals), you must consider the domain of the radical function. The expression inside the square root must be non-negative. This means that you may need to solve an inequality to determine the possible values of x that make the expression inside the square root greater than or equal to zero. This domain restriction can help you identify extraneous solutions more easily.

Forgetting to Check for Extraneous Solutions

This is the most common mistake when solving radical equations. Squaring both sides can introduce extraneous solutions, so checking your solutions is not optional—it's a critical step. If you skip this step, you may end up with incorrect answers.

Incorrectly Squaring Binomials

When squaring an expression like (7 - x)², it's essential to use the correct expansion: (7 - x)² = (7 - x)(7 - x) = 49 - 14x + x². A common mistake is to incorrectly square each term individually, which would give 49 + x², omitting the middle term -14x. This error will lead to an incorrect quadratic equation and, consequently, incorrect solutions.

Not Isolating the Radical First

Before squaring both sides, you must isolate the radical term. If you square both sides without isolating the radical, you'll end up with a more complex equation that is harder to solve. Isolating the radical simplifies the process and makes it easier to eliminate the radical.

Ignoring Domain Restrictions

The expression inside a square root must be non-negative. Ignoring this restriction can lead to incorrect solutions. Always consider the domain of the radical function and check if your solutions fall within the valid domain.

Making Algebraic Errors

Solving radical equations involves multiple steps, each of which requires careful algebraic manipulation. Errors in simplifying, factoring, or solving equations can lead to incorrect solutions. It's crucial to double-check your work at each step to avoid these errors.

While solving radical equations might seem like an abstract mathematical exercise, it has numerous real-world applications in various fields.

Physics

Radical equations frequently appear in physics, particularly in problems involving motion, energy, and gravity. For example, the period of a pendulum is given by the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Solving for L or g would involve solving a radical equation.

Engineering

Engineers use radical equations in various calculations, such as determining the strength of materials, designing structures, and analyzing fluid flow. For instance, the velocity of an object falling under gravity can be calculated using the equation v = √(2gh), where v is the velocity, g is the acceleration due to gravity, and h is the height. Solving for h would involve a radical equation.

Finance

In finance, radical equations can be used in calculations involving compound interest and annuities. For example, the formula for the future value of an investment compounded annually is A = P(1 + r)ⁿ, where A is the future value, P is the principal, r is the interest rate, and n is the number of years. Solving for r would involve a radical equation.

Computer Graphics

Radical equations are used in computer graphics for various purposes, such as calculating distances, determining intersections, and creating realistic lighting effects. For example, the distance between two points in 3D space can be calculated using the distance formula, which involves a square root.

Navigation

Radical equations are used in navigation systems, such as GPS, to calculate distances and positions. These systems rely on complex mathematical models that often involve radical equations.

To solidify your understanding of solving radical equations, let's work through a few practice problems:

  1. Solve for x: √(2x + 3) = 5
  2. Solve for x: x = √(x + 2)
  3. Solve for x: √(x + 1) + 5 = x
  4. Solve for x: √(3x - 2) - √(x + 4) = 0

Mastering the art of solving equations involving radicals is a valuable skill in mathematics. It requires a systematic approach, careful attention to detail, and a thorough understanding of the underlying principles. By following the steps outlined in this guide, you can confidently tackle a wide range of radical equation problems. Remember to always isolate the radical, square both sides (or raise to the appropriate power), solve the resulting equation, and, most importantly, check for extraneous solutions. With practice and perseverance, you'll become proficient in solving these types of equations and appreciate their applications in various real-world contexts.