Solving $x^2 - 7x + 12 = 0$ A Comprehensive Guide

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This article delves into the process of solving the quadratic equation x2−7x+12=0x^2 - 7x + 12 = 0. Quadratic equations, a fundamental concept in mathematics, appear in various fields, from physics to engineering, and even in everyday problem-solving. Understanding how to solve them is a crucial skill. We'll explore different methods, discuss the underlying principles, and provide a comprehensive guide to tackling such equations. The equation we're focusing on, x2−7x+12=0x^2 - 7x + 12 = 0, is a classic example that can be solved using multiple techniques, making it an excellent starting point for our exploration. Let's embark on this mathematical journey and unravel the solutions together.

Understanding Quadratic Equations

Before we dive into solving our specific equation, it's essential to understand the general form and characteristics of quadratic equations. A quadratic equation is a polynomial equation of the second degree. The general form is given by ax2+bx+c=0ax^2 + bx + c = 0, where 'a', 'b', and 'c' are constants, and 'a' is not equal to zero. The 'x' represents the variable we are trying to solve for. The solutions to a quadratic equation are also known as roots or zeros. These roots represent the values of 'x' that make the equation true. A quadratic equation can have two distinct real roots, one repeated real root, or two complex roots. The nature of the roots depends on the discriminant, which is given by the formula b2−4acb^2 - 4ac. If the discriminant is positive, there are two distinct real roots; if it's zero, there is one repeated real root; and if it's negative, there are two complex roots. Understanding these fundamental concepts is crucial for effectively solving any quadratic equation. Different methods, such as factoring, completing the square, and using the quadratic formula, can be employed to find these roots. The choice of method often depends on the specific equation and the solver's preference. For instance, equations that can be easily factored are often solved using the factoring method, while the quadratic formula provides a universal solution for any quadratic equation. In our case, the equation x2−7x+12=0x^2 - 7x + 12 = 0 lends itself well to factoring, but we will also explore other methods to illustrate their application and versatility.

Method 1: Factoring the Quadratic Equation

The first method we'll use to solve the equation x2−7x+12=0x^2 - 7x + 12 = 0 is factoring. Factoring involves breaking down the quadratic expression into a product of two binomials. This method is particularly efficient when the quadratic equation has integer roots. To factor the equation, we need to find two numbers that multiply to 'c' (the constant term) and add up to 'b' (the coefficient of the 'x' term). In our equation, x2−7x+12=0x^2 - 7x + 12 = 0, 'c' is 12 and 'b' is -7. We need to find two numbers that multiply to 12 and add up to -7. After considering the factors of 12 (1, 2, 3, 4, 6, 12), we can identify that -3 and -4 satisfy these conditions because (-3) * (-4) = 12 and (-3) + (-4) = -7. Now we can rewrite the quadratic equation in factored form: (x−3)(x−4)=0(x - 3)(x - 4) = 0. For this equation to be true, either (x−3)(x - 3) must equal zero or (x−4)(x - 4) must equal zero. Setting each factor to zero gives us two simple linear equations: x−3=0x - 3 = 0 and x−4=0x - 4 = 0. Solving these equations, we find x=3x = 3 and x=4x = 4. Therefore, the solutions to the quadratic equation x2−7x+12=0x^2 - 7x + 12 = 0 are x=3x = 3 and x=4x = 4. Factoring is a powerful technique, especially when the roots are integers, as it provides a straightforward and intuitive way to find the solutions. However, not all quadratic equations can be easily factored, which leads us to explore other methods.

Method 2: Using the Quadratic Formula

Another powerful method for solving quadratic equations is using the quadratic formula. This formula provides a universal solution for any quadratic equation of the form ax2+bx+c=0ax^2 + bx + c = 0. The quadratic formula is given by: x=−b±b2−4ac2ax = \frac{-b ± \sqrt{b^2 - 4ac}}{2a}. In our equation, x2−7x+12=0x^2 - 7x + 12 = 0, we can identify the coefficients as follows: a=1a = 1, b=−7b = -7, and c=12c = 12. Substituting these values into the quadratic formula, we get: x=−(−7)±(−7)2−4(1)(12)2(1)x = \frac{-(-7) ± \sqrt{(-7)^2 - 4(1)(12)}}{2(1)}. Simplifying this expression, we have: x=7±49−482x = \frac{7 ± \sqrt{49 - 48}}{2}. Further simplification yields: x=7±12x = \frac{7 ± \sqrt{1}}{2}. Since the square root of 1 is 1, we have: x=7±12x = \frac{7 ± 1}{2}. Now we have two possible solutions: x=7+12=82=4x = \frac{7 + 1}{2} = \frac{8}{2} = 4 and x=7−12=62=3x = \frac{7 - 1}{2} = \frac{6}{2} = 3. Therefore, the solutions to the quadratic equation x2−7x+12=0x^2 - 7x + 12 = 0 using the quadratic formula are x=3x = 3 and x=4x = 4, which confirms our solutions obtained through factoring. The quadratic formula is particularly useful when factoring is difficult or not possible, as it provides a direct method for finding the roots. It is a cornerstone of algebra and a valuable tool for solving a wide range of mathematical problems.

Method 3: Completing the Square

Completing the square is another method for solving quadratic equations. It involves transforming the quadratic equation into a perfect square trinomial, which can then be easily solved. Let's apply this method to our equation, x2−7x+12=0x^2 - 7x + 12 = 0. The first step is to rewrite the equation by moving the constant term to the right side: x2−7x=−12x^2 - 7x = -12. Next, we need to complete the square on the left side. To do this, we take half of the coefficient of the 'x' term, square it, and add it to both sides of the equation. The coefficient of 'x' is -7, so half of it is -7/2, and squaring it gives us (−7/2)2=49/4(-7/2)^2 = 49/4. Adding 49/4 to both sides, we get: x2−7x+494=−12+494x^2 - 7x + \frac{49}{4} = -12 + \frac{49}{4}. Now, the left side is a perfect square trinomial, which can be written as: (x−72)2(x - \frac{7}{2})^2. On the right side, we need to combine the terms: −12+494=−484+494=14-12 + \frac{49}{4} = \frac{-48}{4} + \frac{49}{4} = \frac{1}{4}. So our equation becomes: (x−72)2=14(x - \frac{7}{2})^2 = \frac{1}{4}. Now we can take the square root of both sides: x−72=±14x - \frac{7}{2} = ±\sqrt{\frac{1}{4}}. This gives us: x−72=±12x - \frac{7}{2} = ±\frac{1}{2}. Now we have two possible equations: x−72=12x - \frac{7}{2} = \frac{1}{2} and x−72=−12x - \frac{7}{2} = -\frac{1}{2}. Solving for 'x' in the first equation: x=72+12=82=4x = \frac{7}{2} + \frac{1}{2} = \frac{8}{2} = 4. Solving for 'x' in the second equation: x=72−12=62=3x = \frac{7}{2} - \frac{1}{2} = \frac{6}{2} = 3. Thus, the solutions to the quadratic equation x2−7x+12=0x^2 - 7x + 12 = 0 using the method of completing the square are x=3x = 3 and x=4x = 4, consistent with our previous results. Completing the square is a versatile method that can be used even when factoring is not straightforward, and it provides a deeper understanding of the structure of quadratic equations.

Verifying the Solutions

After finding the solutions to a quadratic equation, it's crucial to verify them to ensure accuracy. This can be done by substituting the solutions back into the original equation and checking if the equation holds true. We found that the solutions to x2−7x+12=0x^2 - 7x + 12 = 0 are x=3x = 3 and x=4x = 4. Let's verify these solutions. First, substitute x=3x = 3 into the equation: (3)2−7(3)+12=9−21+12=0(3)^2 - 7(3) + 12 = 9 - 21 + 12 = 0. Since the equation holds true, x=3x = 3 is a valid solution. Next, substitute x=4x = 4 into the equation: (4)2−7(4)+12=16−28+12=0(4)^2 - 7(4) + 12 = 16 - 28 + 12 = 0. Again, the equation holds true, so x=4x = 4 is also a valid solution. By verifying the solutions, we can be confident that we have correctly solved the quadratic equation. This practice is particularly important in more complex problems where errors can easily occur. Verifying the solutions not only confirms the correctness of our calculations but also reinforces our understanding of the equation and its properties. In the context of quadratic equations, verification is a simple yet effective way to ensure the reliability of our results.

Conclusion

In conclusion, we have explored various methods for solving the quadratic equation x2−7x+12=0x^2 - 7x + 12 = 0. We successfully used factoring, the quadratic formula, and completing the square to find the solutions x=3x = 3 and x=4x = 4. Each method offers a unique approach and highlights different aspects of quadratic equations. Factoring is efficient when the equation can be easily factored, while the quadratic formula provides a universal solution for any quadratic equation. Completing the square offers a deeper understanding of the structure of quadratic equations and is valuable in more advanced mathematical contexts. Furthermore, we emphasized the importance of verifying the solutions to ensure accuracy. By substituting the solutions back into the original equation, we confirmed that x=3x = 3 and x=4x = 4 are indeed the correct solutions. Understanding these methods and the underlying principles is crucial for mastering quadratic equations and applying them in various fields. Quadratic equations are a fundamental concept in mathematics, and the ability to solve them is a valuable skill. This exploration has provided a comprehensive guide to solving quadratic equations, empowering you to tackle similar problems with confidence and precision.